2x^2-8x+42=0

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Solution for 2x^2-8x+42=0 equation: 



2x^2-8x+42=0

a = 2; b = -8; c = +42;
Δ = b2-4ac
Δ = -82-4·2·42
Δ = -272
Delta is less than zero, so there is no solution for the equation

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